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6x^2-12x-48=8
We move all terms to the left:
6x^2-12x-48-(8)=0
We add all the numbers together, and all the variables
6x^2-12x-56=0
a = 6; b = -12; c = -56;
Δ = b2-4ac
Δ = -122-4·6·(-56)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{93}}{2*6}=\frac{12-4\sqrt{93}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{93}}{2*6}=\frac{12+4\sqrt{93}}{12} $
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